# Program to find the frequency of each element in the array

In this program, we have an array of elements to count the occurrence of its each element. One of the approaches to resolve this problem is to maintain one array to store the counts of each element of the array. Loop through the array and count the occurrence of each element as frequency and store it in another array fr.

1. 1    2   8  3   2   2   2   5   1

In the given array, 1 has appeared two times so its frequency be 2 and 2 has appeared four times so have frequency 4 and so on.

### Algorithm

• STEP 1: START
• STEP 2: INITIALIZE arr[] ={1, 2, 8, 3, 2, 2, 2, 5, 1 }.
• STEP 3: CREATE fr[] of arr[] length.
• STEP 4: SET visited = -1.
• STEP 5: REPEAT STEP 6 to STEP 9 for(i=0;i<arr.length;i++)
• STEP 6: SET count = 1
• STEP 7: REPEAT STEP 8 for(j=i+1;j<arr.length;j++)
• STEP 8: if(arr[i]==arr[j]) then
count++
fr[j] =visited
• STEP 9: if(fr[i]!=visited) then
fr[i]=count
• STEP 10: PRINT “————“
• STEP 11: PRINT “Element | Frequency”
• STEP 12: PRINT “————-“
• STEP 13: REPEAT STEP 14 for(i=0;i<fr.length;i++)
• STEP 14: if(fr[i]!=visited) then
PRINT arr[i] and fr[i]
• STEP 15: PRINT “————-“
• STEP 16: END

### Program:

1. public class Frequency {
2.     public static void main(String[] args) {
3.         //Initialize array
4.         int [] arr = new int [] {1, 2, 8, 3, 2, 2, 2, 5, 1};
5.         //Array fr will store frequencies of element
6.         int [] fr = new int [arr.length];
7.         int visited = -1;
8.         for(int i = 0; i < arr.length; i++){
9.             int count = 1;
10.             for(int j = i+1; j < arr.length; j++){
11.                 if(arr[i] == arr[j]){
12.                     count++;
13.                     //To avoid counting same element again
14.                     fr[j] = visited;
15.                 }
16.             }
17.             if(fr[i] != visited)
18.                 fr[i] = count;
19.         }
20.
21.         //Displays the frequency of each element present in array
22.         System.out.println(“—————————————“);
23.         System.out.println(” Element | Frequency”);
24.         System.out.println(“—————————————“);
25.         for(int i = 0; i < fr.length; i++){
26.             if(fr[i] != visited)
27.                 System.out.println(”    ” + arr[i] + ”    |    ” + fr[i]);
28.         }
29.         System.out.println(“—————————————-“);
30.     }}

Output:

``` ----------------------------------------
Element | Frequency
----------------------------------------
1           |         2
2           |         4
8           |         1
3           |         1
5           |         1
----------------------------------------```